Atomic structure and properties. (Chapter 3)

Содержание

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Picture of the Atom Electromagnetic radiation and Atomic Spectra The Nature

Picture of the Atom
Electromagnetic radiation and Atomic Spectra
The Nature of

Electron and Atomic Orbitals
Many-electron atoms
Atomic properties and Periodicity
Nuclear chemistry

Chapter 3

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3.1.1 Atomic concept, 3.1.2 Subatomic particles, 3.1.3 Atomic structure: first ideas Part I

3.1.1 Atomic concept,
3.1.2 Subatomic particles,
3.1.3 Atomic structure: first ideas

Part

I
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Dalton Atomic Theory Elements are made of tiny particles called atoms

Dalton Atomic Theory
Elements are made of tiny particles called atoms
2.

The atoms of a given elements are identical
3. Chemical compounds are formed when atoms combine with one another. A given compound has the same relative numbers and types of atoms
4. Chemical reaction involve reorganization of the atoms. The atom themselves are not changed.

The classical picture of the atom

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J.J. Thomson’s Cathode Tube Charge-to-mass ratio

J.J. Thomson’s Cathode Tube

Charge-to-mass ratio

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The Atom : J. J. Thomson (1856-1940) e/m = -1.76 x 108 C/g Experiment date 1898-1903

The Atom : J. J. Thomson (1856-1940)

e/m = -1.76 x 108

C/g

Experiment date 1898-1903

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The Atom based on Thomson’s experiment A ray of particles is

The Atom based on Thomson’s experiment
A ray of particles is produced
between

two metallic electrodes.
These particles are negatively charged
Since electrons could be produced from electrodes made of various types of metals, all atoms must contain electrons
e/m = -1.76 x 108 C/g
Atoms = neutral! Positive charges are located somewhere.
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Mass of electron Mass of a single electron e= -1.6x10-19 C

Mass of electron

Mass of a single electron
e= -1.6x10-19 C m =

9.11 x 10-31 kg (Millikan)

http://www.youtube.com/watch?v=XMfYHag7Liw

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Rutherford Experiment Ernest Rutherford – 1911 With Thomson Model : a

Rutherford Experiment

Ernest Rutherford – 1911
With Thomson Model : a particles should

travel through the atom without deflection.

http://sun.menloschool.org/~dspence/chemistry/atomic/ruth_expt.html

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Rutherford Experiment

Rutherford Experiment

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The Nucleus Ernest Rutherford – 1911 Conclusion : Dense positive center

The Nucleus

Ernest Rutherford – 1911
Conclusion : Dense positive center with electrons

far from the nucleus
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Modern View

Modern View

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3.2. Electromagnetic Radiation and Quantization 3.2.1: Electromagnetic Radiation 3.2.2: Quantization 3.2.3: The Atomic Spectrum of Hydrogen

3.2. Electromagnetic Radiation and Quantization

3.2.1: Electromagnetic Radiation
3.2.2: Quantization
3.2.3: The Atomic Spectrum

of Hydrogen
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Spectrum

Spectrum

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Electromagnetic radiation Light X-ray MRI Microwave Travel like a wave Travel with the speed of light

Electromagnetic radiation

Light

X-ray

MRI

Microwave

Travel like a wave
Travel with the speed of light

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Electromagnetic Radiation Electromagnetic Radiation = a way for energy to travel.

Electromagnetic Radiation

Electromagnetic Radiation = a way for energy to travel.
2 oscillating

fields (H and E)
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ELECTROMAGNETIC RADIATION

ELECTROMAGNETIC RADIATION

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Electromagnetic Radiation - Characteristics λ = wavelength = distance between two

Electromagnetic Radiation - Characteristics

λ = wavelength = distance between two peaks

or two troughs in a wave. (m)
= frequency = number of waves / s at a specific point of space. (s-1 or Hz)
Because speed = c
= 3x108 m/s

The radiation with the shortest wavelength has the highest frequency

λ ∞ 1/ν

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Radio in the 909kHz. What wavelength does it correspond to? λ

Radio in the 909kHz. What wavelength does it correspond to?

λ =

c/ν = 330 m

C = 2.998 108 ms-1
ν = 909. 103 s-1

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Nature of Matter At the end of the 19th century :

Nature of Matter

At the end of the 19th century :
Matter

≠ Energy
Matter = particles and Energy = electromagnetic radiations
Max Planck and the black body radiation :

Classic : matter can absorb or emit any quantity of energy ? no maximum ? infinite intensity at very low wavelength.
Quantum : Energy could only be gained or emitted in whole number multiples of hν. h = Plank’s constant = 6.626x10-34Js

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Photoelectric effect When UV radiation hits a metal surface, electrons are

Photoelectric effect

When UV radiation hits a metal surface, electrons are ejected

– photoelectric effect. (in 1905 explained by Albert Einstein using a quantum approach)
hν = Φ + EKE
Φ - work function – minimum energy required to remove the electron
EKE – kinetic energy of the ejected electron

Albert Einstein Theory :
Energy itself is quantified and radiation could be seen as a stream of particles (photons)!

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E = h x ν E = 6.63 x 10-34 (J•s)

E = h x ν

E = 6.63 x 10-34 (J•s) x

3.00 x 10 8 (m/s) / 0.154 x 10-9 (m)

E = 1.29 x 10 -15 J

E = h x c / λ

When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the photons if the wavelength of the X rays is 0.154 nm.

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Dual Nature of Light Energy – Mass relationship : A particle

Dual Nature of Light

Energy – Mass relationship :
A particle but also

a wave :
Summary :
- Energy is quantized
- Only discrete units of energy (quanta) could be transferred
- Dual nature of light
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De Broglie 1924 λ = h/mν λ Proportional to h/mν H

De Broglie 1924

λ = h/mν

λ Proportional to h/mν

H :Planck Constant
M :

masse
ν : velocity
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Diffraction What is the wavelength for an electron? Me = 9.11x10-31

Diffraction

What is the wavelength for an electron?

Me = 9.11x10-31 kg
Ve

= 1.0x107 m/s
1 J = 1 kg.m2/s2
6.626x10-34Js

The electron has a WL similar to the spacing of atoms in a crystal.
Confirmed for Ni crystal.
Diffraction : result of light scattered from a regular array of points or lines.

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How to test the wave properties of an electron?

How to test the wave properties of an electron?

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How to test the wave properties of an electron?

How to test the wave properties of an electron?

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Diffraction When X-rays are scattered by ordered atoms ? Diffraction pattern.

Diffraction

When X-rays are scattered by ordered atoms ? Diffraction pattern.

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Conclusion All matter exhibits both particulate and wave properties. Large particles

Conclusion

All matter exhibits both particulate and wave properties.
Large particles : mainly

particle
Small particles : mainly wave
Intermediate particles (electron) : both
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Atomic Spectrum of Hydrogen When a high energy discharge is passed

Atomic Spectrum of Hydrogen

When a high energy discharge is passed through

H2 ? H-H breaks ? excited H atoms.
Release of energy ? Emission spectrum.
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Table 3.4. The atomic spectrum of hydrogen

Table 3.4. The atomic spectrum of hydrogen

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Atomic Spectrum of Hydrogen Why do we have a line spectrum

Atomic Spectrum of Hydrogen

Why do we have a line spectrum for

H ?
Only certain energies are allowed for the electron in the hydrogen atom.
Energy is quantized!
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3.3.2: The Bohr Model

3.3.2: The Bohr Model

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The Bohr Model General Idea : The electron in a hydrogen

The Bohr Model

General Idea :
The electron in a hydrogen atom moves

around the nucleus only in certain allowed circular obits.
Bohr used classical physics to calculate the radii of these orbits.
At an infinite distance E=0 (n=∞)
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The Bohr Model Example : Energy emitted from n=6 to ground

The Bohr Model

Example : Energy emitted from n=6 to ground state

:
The negative sign means that the electron is more tightly bound when
n=1 than when n=6
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Wave Function and Atomic Orbitals 3.5.1 Wave properties of matter, Heisenberg

Wave Function and Atomic Orbitals

3.5.1 Wave properties of matter, Heisenberg uncertainty

principle
3.5.2 Wave-functions and Schrödinger equation
3.5.3 Shapes of atomic orbitals
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De Broglie All moving particles have wave properties λ= h mu

De Broglie

All moving particles have wave properties

λ=

h

mu

= Wavelength
h = Planck

Constant
m = Mass
u = Velocity of the particle

The electron bound to the nucleus is similar to a standing wave.
The waves do not travel.
Node = no displacement of the wave = each end.
? Always a whole number of half-WL.

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2.2 SCHRONDINGER EQUATION Enter

2.2 SCHRONDINGER EQUATION

Enter

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Quantum Mechanical Description of the Atom Heisenberg – de Broglie –

Quantum Mechanical Description of the Atom

Heisenberg – de Broglie – Schrödinger
Only

certain circular orbits have a circumference into which a whole number of wavelength of the standing electron will fit.

ψ = wave function : describes x, y, z of the electron
H = Hamiltonian operator
E = Total Energy of the atom (Ep e-p + Ek e)

– probability of finding an electron at some point is proportional to Ψ Ψ *. Ψ * is the complex conjugate

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The Schrödinger equation The probability distributions and allowed energy levels for

The Schrödinger equation

The probability distributions and allowed energy levels for electrons

in atoms and molecules can be calculated using the Schrödinger equation

– second order differential equation

– equation has a large number of different solutions
» each corresponds to a different possible probability distribution for the electron

– probability of finding an electron at some point is proportional to Ψ Ψ *. Ψ * is the complex conjugate

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Schrodinger Wave Equation

Schrodinger Wave Equation

 

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Kinetic Energy of the Electron Motion Potential Energy of the Electron.

Kinetic Energy of the
Electron Motion

Potential Energy of the
Electron. The

result of
electrostatic attraction
between the electron
and the nucleus. It is
commonly designated as V

 

 

Hamiltonian for one Electron

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Kinetic Energy Potential Energy

 

 

 

Kinetic Energy

Potential Energy

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Cartesian and Spherical Coordinate

Cartesian and Spherical Coordinate

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The wavefunction Atomic wavefunctions are usually expressed in spherical polar coordinates

The wavefunction

Atomic wavefunctions are usually expressed in spherical polar coordinates

give value of Ψ at any point in space specified by r, θ and φ
Can write Ψ(r, θ, φ)=R(r) Y(θ, φ)
– R(r) is radial part of wavefunction
– Y(θ, φ) is angular part of wavefunction

Quantum Numbers and Atomic Wavefunctions

https://www.youtube.com/watch?v=sT8JIn7Q_Fo
https://www.youtube.com/watch?v=NpgKGIaE9Zc

x = rsinθcosφ
y = rsinθsinφ
z = rcosθ

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Homework-2 Please solve problems ; Chapter 3 6, 9, 10, 12,

Homework-2

Please solve problems ;
Chapter 3
6, 9, 10, 12, 14, 16 and

17
Due on Wednesday. Recitation time
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Wave Equation for the Hydrogen Atom – R(r) is radial part

Wave Equation for the Hydrogen Atom
– R(r) is radial part of

wavefunction
Describes electrons density at different
distances from the nucleus
– Y(θ, φ) is angular part of wavefunction
Describes the shape of the orbitals and
its orientation in space.
In other words:
How the probability changes from point to
point at a given distance from the
center of the atom.

x = rsinθcosφ
y = rsinθsinφ
z = rcosθ

Ψ(x, y, z)= Ψ(r, θ, φ) = R(r) Y(θ, φ)

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Quantum numbers : Quantum numbers : n = principal quantum number

Quantum numbers :

Quantum numbers :
n = principal quantum number : size

and energy of the orbital
l = angular momentum quantum number : 0 to n-1 : shape of the orbital
ml = magnetic quantum number : -l to +l : orientation in space of the angular momentum
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Radial and Angular Wave Function for 1s derived from Schrodinger Equation

Radial and Angular Wave Function for 1s derived from Schrodinger Equation

 

 

 

 

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Plot of Radial Wave Function = f(r)

Plot of Radial Wave Function = f(r)

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s orbitals Size : 1s Energy : 1s Surface of 0

s orbitals

Size : 1s<2s<3s.
Energy : 1s<2s<3s.
Surface of 0 probability = nodal

surface / node.
Number of node = n-1 for s orbitals.
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Physical Meaning of Orbitals The wave function has no easy physical

Physical Meaning of Orbitals

The wave function has no easy physical meaning.
The

square of the WV at a certain point in space = probability to find an electron near that point = probability distribution.

For 1s orbital : arbitrary accepted size = radius of the sphere that encloses 90% of total electron probability.

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a1 = 52.9pm radius at n =1 for hydrogen

 

a1 = 52.9pm radius at n =1 for hydrogen

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a1 = 52.9pm radius at n =1 for hydrogen

 

a1 = 52.9pm radius at n =1 for hydrogen

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p orbitals Two lobes separated by a node. Sine function :

p orbitals

Two lobes separated by a node.
Sine function : +

and - ? same for the orbital.
Px, Py, Pz following their orientation
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d orbitals 2 different shapes : dxz,dyz,dxy, dx2-y2 and dz2

d orbitals

2 different shapes : dxz,dyz,dxy, dx2-y2 and dz2

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f orbitals Very complex shapes

f orbitals

Very complex shapes

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Schrödinger Equation Each solution ψ of the Schrödinger equation has a

Schrödinger Equation

Each solution ψ of the Schrödinger equation has a specific

value for E.
A specific wave function for a given electron = orbital
An orbital ≠ orbit.
How does an electron move in an orbit? We don’t know!
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Heisenberg uncertainty principle There is a fundamental limitation to just how

Heisenberg uncertainty principle

There is a fundamental limitation to just how precisely

we can know both the position and the momentum of a particle at a given time.
Negligible for macro particles (ball, etc.) but not for small particles!
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The Hydrogen Atom : summary The quantum mechanical model : electron

The Hydrogen Atom : summary

The quantum mechanical model : electron =

wave
Series of wave function (orbitals) that describe the possible energies and spatial distributions available to the electrons.
Heisenberg : the electron motion can’t be defined.
The square of the WF = probability distribution of the electron in an orbital.
The size of the orbital is arbitrarily defined .
Surface that contains 90% of the total electron probability.
The H atom has many orbitals.
In the ground state : e- in 1s.
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Polyelectronic Model Schrödinger equation can be solved exactly only for hydrogen.

Polyelectronic Model

Schrödinger equation can be solved exactly only for hydrogen.
Schrödinger equation

cannot be solved exactly for polyelectronic atoms.
It has to be approximated : SCF : Self-Consistent Field by Hartree.
1- A WF (orbital) is guessed for each electron except for electron 1.
2- Schrödinger equation is solved for electron 1
3- The repulsion between 1 and the others electrons are computed
4- ψ1 is found
5- ψ2, etc. are computed
6- The entire process start again until a self-consistent field is obtained
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Self-Consistent Field Method http://www.youtube.com/watch?v=UVkTuOwfOh0

Self-Consistent Field Method

http://www.youtube.com/watch?v=UVkTuOwfOh0

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https://www.youtube.com/watch?v=A6DiVspoZ1E Review this link at home

https://www.youtube.com/watch?v=A6DiVspoZ1E

Review this link at home

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Many Electron Atoms Electron spin, Aufbau principle, Anomalies in electronic configuration,

Many Electron Atoms

Electron spin,
Aufbau principle,
Anomalies in electronic configuration, Structure

of Periodic table

Part V

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Electron Spin and Pauli Principle A 4th quantum number describe the

Electron Spin and Pauli Principle

A 4th quantum number describe the electron

: ms : electron spin quantum number.
The electron doesn’t really “spin” = name for the intrinsic angular moment.
ms = +1/2 or -1/2
Pauli exclusion principle : in a given atom no two electrons can have the same set of four quantum numbers.
– An orbital can hold only two electrons and they must have opposite spin.
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History of the Periodic Table Dmitri Mendeleev : ми́трий Менделе́ев One

History of the Periodic Table
Dmitri Mendeleev : ми́трий Менделе́ев
One of first

to arrange known elements into a chart
Allowed prediction of element properties
Arranged known elements according to increasing atomic masses
Mendeleev first stated the periodic law
“The properties of the elements are a periodic function of their atomic
masses”

1834 – 1907
Saint Petersburg - Russia

Later, after more observations, the table was correctly arranged in ORDER OF INCREASING ATOMIC NUMBER

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The Aufbau Principle Principle to populate orbitals.

The Aufbau Principle

Principle to populate orbitals.

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Valence electrons Valence electrons = electrons from the outermost principal quantum

Valence electrons

Valence electrons = electrons from the outermost principal quantum level

of an atom.
Group : Elements in a column : Same valence configuration
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Rules

Rules

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Rules After 4s2, we fill 3d. Mn : [Ar]4s23d5 – Fe

Rules

After 4s2, we fill 3d.
Mn : [Ar]4s23d5 – Fe [Ar]4s23d6
Additional Rules:
The

(n+1) orbitals always fill before the nd orbitals.
After lanthanum, the lanthanide series occur. ? filling of 4f instead of 5d
After actinium, the actinide series occur. ? filling 5f instead of 6d
Groups 1A?8A indicate the total number of valance electrons.
Groups 1A?8A are main group elements.
2 exceptions to learn by heart : Cr [Ar]4s1d5 and Cu [Ar]4s13d10
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Rules Element above 118 are generally unstable G contain 9 orbitals

Rules

Element above 118
are generally unstable

G contain 9 orbitals l = n-1

= 4 so -4,-3,-2, -1, 0, 2, 3, 4 each
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Rules

Rules

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Hund’s Rule The lowest energy configuration for an atom is the

Hund’s Rule

The lowest energy configuration for an atom is the one

having the maximum number of unpaired electrons allowed by the Pauli Principle.
Configuration of Ne? 1s22s22p6
Configuration of Na? [Ne]3s1
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Pauli Exclusion Principle Pauli Exclusion principle ; no two electrons in

Pauli Exclusion Principle
Pauli Exclusion principle ; no two electrons in an

atom can have the same quantum numbers n, l, ml, and ms
– this means that an orbital can never have more than two electrons in it
Hund’s Rule
Hund’s rule of maximum multiplicity requires that electrons be placed in orbitals to give the maximum total spin possible (the maximum number of parallel spin)
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Penetration Effect Why do we fill s, p and then d?.

Penetration Effect

Why do we fill s, p and then d?.
Core

electrons : 1s, 2s and 2p are shielding 3s, 3p, 3d from the nuclear charge.
Even if 3s has a max around 200pm, it has a small/significant prob. of being quite close to the nucleus ? Penetration effect.
3p has less chance to be near the nucleus
3d shows much less penetration than 3p. E3s < E3p < E3d
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Penetration Effect The penetration effect also explains why 4s is filled

Penetration Effect

The penetration effect also explains why 4s is filled before

3d.

Potassium : 1S22S22P63S23P64S1 rather than 1S22S22P63S23P63d1

An electron in a 4S penetrate much more than an electron in a 3d orbital, as shown
Graphically. (qualitative explanation)

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4s 5g 5s 3p 3s 2p 2s Slater rules provide an

4s

5g

5s

3p

3s

2p

2s

Slater rules provide an approximate
Guide explain why certain orbitals
fill

before others.
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https://en.wikipedia.org/wiki/Effective_nuclear_charge

https://en.wikipedia.org/wiki/Effective_nuclear_charge

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Slater’s Rules The rules were devised semi-empirically by John C. Slater

Slater’s Rules The rules were devised semi-empirically by John C. Slater and published in 1930

Identify Zeff

(as a measure of attraction) for any electron
Z* = Z – S
Where Z = nuclear charge
S = shielding constant

https://www.youtube.com/watch?v=5flvrGhT40U & https://www.youtube.com/watch?v=9mXQJUrOhxk
https://www.youtube.com/watch?v=RSf98oxyVm8

Rule-1. The atoms electronic structure is written in order of increasing quantum numbers n and l grouped as follows:
(1s) (2s,2p) (3s,3p) (3d) (4s,4p) (4d) (4f) (5s, 5p) (5d) etc.
Rule-2. Each group to the right do not shield electrons to their left.

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Slater’s Rules The rules were devised semi-empirically by John C. Slater

Slater’s Rules The rules were devised semi-empirically by John C. Slater and published in 1930

Rules for

determining S
S = shielding constant

https://www.youtube.com/watch?v=5flvrGhT40U & https://www.youtube.com/watch?v=9mXQJUrOhxk
https://www.youtube.com/watch?v=RSf98oxyVm8

Rule-1. The atoms electronic structure is written in order of increasing quantum numbers n and l grouped as follows:
(1s) (2s,2p) (3s,3p) (3d) (4s,4p) (4d) (4f) (5s, 5p) (5d) etc.
Rule-2. Each group to the right do not shield electrons to their left.

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Slater’s Rules for determining S for a specific electron The shielding

Slater’s Rules for determining S for a specific electron

The shielding constant

(S) ns and np valence electrons:
3a) Each electron in the same (ns, np) group contributes 0.35 to the value of S for each other electron in the group.
Except. A 1s electron contributes 0.30 to S of another 1s electron.
EXAMPLE: 2s2p5, in a particular 2p electron has 6 other electron in (2s, 2p) group. Each of these contribute 0.35 to the value of S, for a total contribution to S of 6×0.35=2.10
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Slater’s Rules for determining S for a specific electron Rule -3b:

Slater’s Rules for determining S for a specific electron

Rule -3b: Each

electron in n-1 group contribute 0.85 to S
Rule -3c: Each electron in n-2 group or lower shells contribute 1.00 to S
EXAMPLE: 3s electrons of sodium (1s22s2p63S1) , there are 8 electrons in n-1 (2s, 2p) group, each of these contribute 0.85 to the value of S, for a total contribution to S of 8×0.85=6.80. There are two electrons in n-2(1S) 2 ×1 = 2, S = 8.80
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Z* for Na = Z – S = 11 – 8.8 = 2.2

Z* for Na = Z – S = 11 – 8.8

= 2.2
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Slater’s Rules for determining S for a specific electron Rule -4a:

Slater’s Rules for determining S for a specific electron

Rule -4a: Each

electron in nd and nf valence
Each electron in the same group (nd) or (nf) group contribute 0.35 to the value of S to each other electron in the group (same rule as 3a)
Rule -4b:
Each electron in groups to the left contribute 1 to the value of S.
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Nickel Use slater rules to calculate the shielding constant S and

Nickel
Use slater rules to calculate the shielding constant S and effective

nuclear charge of 3d and 4s electrons. Compare

Explain why the most common oxidation state
of Ni have [Ar]3d8

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Solution Rule-1 : the electron configuration is written using slater’s groupings:

Solution

Rule-1 : the electron configuration is written using slater’s groupings:
(1s2)(2s2, 2p6)(3s2,

3p6)(3d8)(4s2)
To calculate S for 3d valence electron:
Rule 4a : each electron in the group(3d8) contributes 0.35 to S. Total contribution = 7×0.35=2.45
Rule 4b : each electron in the group to the left of (3d8) Contribute 1 to S. Total contribution = 18×1=18.00
Total S = 2.45 +18.00= 20.45
The effective nuclear charge Z*=28-20.45=7.55
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Solution Rule-1 : the electron configuration is written using slater’s groupings:

Solution

Rule-1 : the electron configuration is written using slater’s groupings:
(1s2)(2s2, 2p6)(3s2,

3p6)(3d8) (4s2)
To calculate S for 4s valence electron:
Rule 3a : each electron in the 4s group contribute 0.35 1× 0.35
Rule 3b : each electron in the n-1 group contribute 0.85 (0.85.16) = 13.60
Rule 3c : each electron on the left of n-1 Contribute 1 to S. Total contribution = 10×1=10.00
Total S = 0.35 + 13.60 + 10.00= 23.95
The effective nuclear charge Z*=28-23.95=4.05
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Comparison of The effective nuclear charge 3d electrons The effective nuclear

Comparison of The effective nuclear charge

3d electrons
The effective nuclear charge


Z*=28-20.45=7.55
4s electrons
Z*=28-23.95=4.05
Ni : [Ar]3d8
All transition Metals loose ns electrons more readily than (n-1) d electrons
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Periodic Properties of Atoms : Ionization Energy Ionization Energy : Energy

Periodic Properties of Atoms : Ionization Energy

Ionization Energy : Energy required

to remove an electron from a gaseous atom or ion. IE in kJ or eV (1 eV = 1.602x10-19J)
X(g) ? X+(g) + e-
Koopmans’ theorem : IE of an electron = energy of the orbital from which it came. (Approx because it doesn’t take into account a reorganization)
Al(g) ? Al+(g) + e- I1 = 580 kJ/mol
Al+(g) ? Al2+(g) + e- I2 = 1815 kJ/mol
Al2+(g) ? Al3+(g) + e- I3 = 2740kJ/mol
Al3+(g) ? Al4+(g) + e- I4 = 11 600kJ/mol
[Ne]3s23p1 : First e- come from 3p, second from 3s
I1I4 is very high : Al3+ : 1s22s22p6 : core electrons are bound very tight!
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Trend in Atomic Properties : Ionization Energy IE core electrons >>

Trend in Atomic Properties : Ionization Energy

IE core electrons >>

IE >>

from left to right in a period

X(g)→ X+(g) +1e-

The first ionization energy increases across a period and decreases down a group

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Trend in Atomic Properties : Ionization Energy Li: 1s22s1 (3 electrons)

Trend in Atomic Properties : Ionization Energy

Li: 1s22s1 (3 electrons)
Be:

1s22s2 (3 electrons)
Expected since Be electrons
do shield each other completely

Be: 1s22s2 (3 electrons)
B: 1s22s22p1 (3 electrons)
Expected since 2s electrons
do shield each 2p electrons effectively

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Trend in Atomic Properties : Ionization Energy IE goes down along

Trend in Atomic Properties : Ionization Energy
IE goes down along a

group.
The removed electron is away from the core
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Trend in Atomic Properties : Atomic Radius Atomic Radius: half the

Trend in Atomic Properties : Atomic Radius

Atomic Radius: half the distance

between the nuclei in a molecule consisting of identical atoms.
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END END

END

END

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Alkali Metals – 1A Low melting point Lose easily an electron

Alkali Metals – 1A

Low melting point
Lose easily an electron
Strong reducer
Li

> K > Na

Na and K react more violently with water than Li
due to its high melting point.

Abnormal: Order is due to the hydration energies.

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ρsinφ Δρ Angle = Arc Length radius of the circle

ρsinφ

Δρ

Angle =

Arc Length
radius of the circle

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