How to draw the tolerance zones of transition fit (Seminar 2)

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Step 1: Example We have two joint parts (details): shaft bush

Step 1: Example

We have two joint parts (details):
shaft
bush
(we have empty

place for lower deviation because it is = 0)
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Step 2: Calculation of shaft dimensions We know two limited deviations:

Step 2: Calculation of shaft dimensions

We know two limited deviations:
Upper deviation:

es=dmax- dn
Lower deviation: ei=dmin-dn
dn, dmax & dmin are given:
dn=25 mm
dmax=25.015 mm
dmin=25.005 mm
So es= 25.015-25.000=0.015 mm=15μm (micrometers)
ei=25.005-25.000=0.005 mm=5 μm
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Step 3: Calculation of bush dimensions We know two limited deviations:

Step 3: Calculation of bush dimensions

We know two limited deviations:
Upper deviation:

ES=Dmax- Dn
Lower deviation: EI=Dmin-dn
Dn, Dmax & Dmin are given:
Dn=25 mm
Dmax=25.025 mm
Dmin=25.000 mm
So ES= 25.025-25.000=0.025 mm=25μm
EI=25.000-25.000=0 mm=0 μm
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Step 4: Drawing zero line

Step 4: Drawing zero line

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Step 5: Drawing the shaft tolerance zone

Step 5: Drawing the shaft tolerance zone

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Step 6: Drawing the hole tolerance zone

Step 6: Drawing the hole tolerance zone

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Step 7: Clearances and interferences of transition fit For transition fits

Step 7: Clearances and interferences of transition fit

For transition fits we

have both clearances and interferences but they are go to zero
So
Smin=0 and Nmin=0
And
Smax=Dmax-dmin
Nmax=dmax-Dmin
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Step 8: Calculation of Smax

Step 8: Calculation of Smax

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Step 9: Calculation of Nmax

Step 9: Calculation of Nmax