The ideal gas equation

Содержание

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The ideal gas equation

The ideal gas equation

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Room temperature and pressure, RTP Limitations At RTP, 1 mol of

Room temperature and pressure, RTP

Limitations
At RTP, 1 mol of gas molecules

occupies 24.0 dm3
Conditions are not always room temperature and pressure.
A gas volume depends on temperature and pressure.
Ideal gas equation can calculate a gas volume, V
at any temperature, T
at any pressure, p
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The ideal gas equation pV = nRT

The ideal gas equation

pV = nRT

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Converting units for pV = nRT Before using pV = nRT,

Converting units for pV = nRT

Before using pV = nRT,

convert units to m3, K and Pa
cm3 to m3 × 10−6
dm3 to m3 × 10−3
°C to K + 273
kPa to Pa × 103

100 kPa = 100 × 103 Pa

220 cm3 = 220 × 10−6 cm3

Examples

4.0 dm3 = 4.0 × 10−3 m3

48 °C = 48 + 273 = 321 K

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Calculating gas volumes

Calculating gas volumes

 

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Calculating a relative molecular mass

Calculating a relative molecular mass

 

 

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AN INTRODUCTION TO ATOM ECONOMY KNOCKHARDY PUBLISHING

AN INTRODUCTION TO
ATOM ECONOMY

KNOCKHARDY PUBLISHING

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ATOM ECONOMY In most reactions you only want to make one

ATOM ECONOMY

In most reactions you only want to make one of

the resulting products
Atom economy is a measure of how much of the products are useful
A high atom economy means that there is less waste
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ATOM ECONOMY In most reactions you only want to make one

ATOM ECONOMY

In most reactions you only want to make one of

the resulting products
Atom economy is a measure of how much of the products are useful
A high atom economy means that there is less waste
ATOM ECONOMY

MOLECULAR MASS OF DESIRED PRODUCT x 100
SUM OF MOLECULAR MASSES OF ALL PRODUCTS

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WORKED CALCULATIONS Calculate the atom economy for the formation of 1,2-dichloroethane, C2H4Cl2 Example 1

WORKED CALCULATIONS

Calculate the atom economy for the formation of 1,2-dichloroethane, C2H4Cl2

Example 1

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WORKED CALCULATIONS Calculate the atom economy for the formation of 1,2-dichloroethane,

WORKED CALCULATIONS

Calculate the atom economy for the formation of 1,2-dichloroethane, C2H4Cl2

Equation C2H4 + Cl2 ——> C2H4Cl2
Mr 28 71 99
atom economy = molecular mass of C2H4Cl2 x 100
molecular mass of all products
= 99 x 100 = 100%
99

An ATOM ECONOMY of 100% is typical of an ADDITION REACTION

Example 1

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WORKED CALCULATIONS Calculate the atom economy for the formation of nitrobenzene, C6H5NO2 Example 2

WORKED CALCULATIONS

Calculate the atom economy for the formation of nitrobenzene, C6H5NO2

Example 2

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WORKED CALCULATIONS Calculate the atom economy for the formation of nitrobenzene,

WORKED CALCULATIONS

Calculate the atom economy for the formation of nitrobenzene, C6H5NO2

Equation C6H6 + HNO3 ——> C6H5NO2 + H2O
Mr 78 63 123 18
atom economy = molecular mass of C6H5NO2 x 100
molecular mass of all products
= 123 x 100 = 87.2%
123 + 18

An ATOM ECONOMY of 100% is not possible with a SUBSTITUTION REACTION

Example 2

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WORKED CALCULATIONS Calculate the atom economy for the preparation of ammonia

WORKED CALCULATIONS

Calculate the atom economy for the preparation of ammonia from

the thermal decomposition of ammonium sulphate.

Example 3

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WORKED CALCULATIONS Calculate the atom economy for the preparation of ammonia

WORKED CALCULATIONS

Calculate the atom economy for the preparation of ammonia from

the thermal decomposition of ammonium sulphate.
Equation (NH4)2SO4 ——> H2SO4 + 2NH3
Mr 132 98 17
atom economy = 2 x molecular mass of NH3 x 100
molecular mass of all products
= 2 x 17 = 25.8%
98 + (2 x 17)

In industry a low ATOM ECONOMY isn’t necessarily that bad if you can use some of the other products. If this reaction was used industrially, which it isn’t, the sulphuric acid would be a very useful by-product.

Example 3

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CALCULATIONS Calculate the atom economy of the following reactions (the required

CALCULATIONS

Calculate the atom economy of the following reactions (the required product

is shown in red)
• CH3COCl + C2H5NH2 ——> CH3CONHC2H5 + HCl
• C2H5Cl + NaOH ——> C2H5OH + NaCl
• C2H5Cl + NaOH ——> C2H4 + H2O + NaCl
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CALCULATIONS Calculate the atom economy of the following reactions (the required

CALCULATIONS

Calculate the atom economy of the following reactions (the required product

is shown in red)
• CH3COCl + C2H5NH2 ——> CH3CONHC2H5 + HCl
• C2H5Cl + NaOH ——> C2H5OH + NaCl
• C2H5Cl + NaOH ——> C2H4 + H2O + NaCl

70.2%

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CALCULATIONS Calculate the atom economy of the following reactions (the required

CALCULATIONS

Calculate the atom economy of the following reactions (the required product

is shown in red)
• CH3COCl + C2H5NH2 ——> CH3CONHC2H5 + HCl
• C2H5Cl + NaOH ——> C2H5OH + NaCl
• C2H5Cl + NaOH ——> C2H4 + H2O + NaCl

70.2%

55.8%

33.9%

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OVERVIEW • addition reactions will have 100% atom economy • substitution

OVERVIEW

• addition reactions will have 100% atom economy
• substitution reactions will

have less than 100% atom economy
• high atom economy = fewer waste materials
= GREENER and MORE ECONOMICAL
The percentage yield of a reaction must also be taken into consideration.
• some reactions may have a high yield but a low atom economy
• some reactions may have a high atom economy but a low yield
Reactions involving equilibria must also be considered
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Perform calculations to determine the percentage yield of a reaction Percentage yield

Perform calculations to determine the percentage yield of a reaction

Percentage yield

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In a chemical reaction which is totally efficient all the REACTANTS

In a chemical reaction which is totally efficient all the REACTANTS

are converted into products.
This will give 100% yield.
Most reactions, particularly organic reactions give low yields.
Possible reasons:
Impure reactants.
Product is lost during purification.
Side reactions.
Equilibrium reaction means that a reaction is never completed.
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Definitions Know that: The theoretical yield is the maximum mass of

Definitions

Know that:
The theoretical yield is the maximum mass of products which

would be obtained from the balanced equation.
The actual yield is the mass of products obtained.
The percentage yield = Actual yield x 100%
Theoretical yield
Limiting reactant is the substance present in lowest quantity which determines the actual yield.
Excess – more than the mass determined by the balanced equation is used to maximise product obtained.
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Calculating Percentage (%) Yield 2.3g of sodium reacts with an excess

Calculating Percentage (%) Yield

2.3g of sodium reacts with an excess of

chlorine to produce 4.0g of sodium chloride.

(Ar reactants: Na=23 Cl=35.5 Mr product: NaCl= 58.5)

58.5 x 0.1 =

Theoretical yield of NaCl =

5.85g

What is the percentage yield?

% Yield = Actual yield x 100% Theoretical yield

% Yield = 4.0g x 100% = 5.85g

68%

2Na(s) + Cl2(g) ⇒ 2NaCl(s)

= 0.1 mol Na

Theoretically 0.1 mol Na should yield 0.1 mol NaCl

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Calculating Percentage (%) Yield If 1.2g of magnesium reacts with an

Calculating Percentage (%) Yield

If 1.2g of magnesium reacts with an excess

of oxygen to produce 0.8g of magnesium oxide…

What is the percentage yield?

% Yield = 0.8g x 100% = 2g

40%

2Mg(s) + O2(g) ⇒ 2MgO(s)

(Ar reactants: Mg=24 O=16 Mr product: MgO= 40)

= 0.05 mol Mg

Theoretically 0.05 mol Mg should yield 0.05 mol MgO

40 x 0.05 =

Theoretical yield of MgO =

2g

% Yield = Actual yield x 100% Theoretical yield