Assignment thermal conductivity calculation

sections irrelevant to your households
Use the energy audit data collection table (on Moodle)
Calculate the U-values of your building envelope
Use the science part of the class (slides)
Use the catalog of insulation materials (on Moodle)
Refer to advisory handbook for insulation (if you don’t know what your wall is)
Recommend energy efficiency improvements
Recalculate your envelope U-values after energy efficiency added
Aim for no less than R= 2.2 m2·°C/W

is the insulation value of the material.
E.g.՝ Thermal conductivity of polystyrene W/mօC = 0.028 - 0.035
The lower the lambda, the higher the insulation worth of the material (mind the thickness).

Lambda (Thermal Conductivity) --- Thermal conductivity (also known as Lambda) is the rate at which heat passes through a material, measured in watts per square metre of surface area for a temperature gradient of one kelvin for every metre thickness.This is expressed as W/mK. Thermal conductivity is not affected by the thickness of the product. The lower the conductivity, the more thermally efficient a material is.
Example: PIR Board: Lambda = 0.022 W/mK  Glass Fibre Roll: Lambda = 0.044 W/mK

of material, represent the thermal resistance of individual materials used in the building envelope, or their R-value.
Thickness measured in m2·°C/W       λ
The higher the R-value, the better it resists the heat transfer.
The cumulative thermal resistance of a mixed structure is comprised of individual R-values of the layers in the structure.

R=

R-Value (Thermal Resistance) --- Thermal resistance is the ability of a material to prevent the passage of heat. It’s the thickness of the material (in metres) divided by its conductivity. This is expressed as m2K/W.
If the material consists of several elements, the overall resistance is the total of the resistances of each element. The higher the R-value, the more efficient the insulation.
Example:  PIR Board: 0.022 W/mK and 100mm thick; R-value = 0.1 metres ÷ 0.022 = 4.54 m2K/W  Glass Fibre Roll: 0.044 W/mk and 100mm thick; R-value = 0.1 metres ÷ 0.044 = 2.27 m2K/W

R-value is the thickness of the product in metres ÷ Lambda (thermal conductivity).
Add the R-values of all materials used in the application (including any air gaps) and calculate the reciprocal. The reciprocal = 1 ÷ total of all R-values
Example:  PIR Board 0.022 W/mK100mm thick + Glass Fibre Roll 0.044 W/mK100mm thick Total combined R-value = 4.54 + 2.27 = 6.81 m2K/W  U-value = 1 ÷ 6.81 = 0.147 W/m2K

Table of Insulation & Other Building Material Properties
http://inspectapedia.com/insulation/Insulation_Values_Table.php

loss
Multiple Chambers
Reduced heat transfer
Tight seals
Compression

costs noted are from various sources and are presented for illustrative purposes only. Actual prices internationally and in the local market may vary greatly.

of mineral wool/fiber