Electrochemistry. (Chapter 6)

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Oxidation-Reduction Reactions Electron transfer reactions are called oxidation-reduction or redox reactions.

Oxidation-Reduction Reactions

Electron transfer reactions are called oxidation-reduction or
redox reactions.
Charges

of elements are zero.
Sum of charges of elements in a compound is equal to zero.
Oxidation is loss of electrons. ( losing e )
Reduction is gain of electrons. ( taking e )
Oxidizing agent is Oxidizes other element. (take electron)
Reducing agent is Reduces other element.(loses electron)
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Chapter 6 Oxidation-Reduction Reactions Na → Na+1 + 1e- oxidation Cl2

Chapter 6

Oxidation-Reduction Reactions

Na → Na+1 + 1e- oxidation
Cl2 + 2e- → 2Cl-1 reduction
Here,

Na is reducing agent, while Cl2 is oxidizing agent.
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Chapter 6 Oxidation-Reduction Reactions Example 1 Mg and O2 react to

Chapter 6

Oxidation-Reduction Reactions

Example 1
Mg and O2 react to form MgO. What

are the oxidizing and reducing agents?

Solution
2Mg + O2 → 2MgO
Mg undergoes oxidation process, it is called reducing agent.
O2 undergoes reduction process, it is called oxidizing agent.

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Chapter 6 Oxidation-Reduction Reactions Oxidation States Oxidation states of the elements

Chapter 6

Oxidation-Reduction Reactions

Oxidation States

Oxidation states of the elements must be known

to
balance redox reactions.
Oxidation states of elements in most stable form is zero,
like Fe, Cu, Ag, O2, H2, P, S, P4…etc
Group IA have +1, and Group IIA have +2 and Group IIIA
have +3, Halogens have -1 oxidation states.
Hydrogen in metal hydrates has -1 oxidation state.
Sum of the oxidation states in compounds is zero, in ions
is equal to charge of ion.
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Chapter 6 Oxidation-Reduction Reactions Example 2 Find the oxidation state of

Chapter 6

Oxidation-Reduction Reactions

Example 2
Find the oxidation state of metals in the

following species.
A. FeO B. KMnO4 C. Na2Cr2O7 D. HgOH

Solution
x + -2 = 0 → x = +2
+1 + x + 4(-2) = 0 → x = +7
2(+1) + 2x + 7(-2) = 0 → x = +6
x + (-2) + 1 = 0 → x = + 1